A car, initially at rest, travels 20 m in 4 s along a straight line with constant acceleration. The acceleration of the car is: 1. 0.4 m/s 2 2. 9.8 m/s 2 3. 4.9 m/s 2 4. 1.3 m/s 2 5. 2.5 m/s 2

Step-by-step explanation:

Using the equation of motion S = ut + 1/2at² where;

S is the distance travelled = 20m

u is the initial velocity = 0m/s (car starts from rest)

a is the acceleration = ?

t is the time taken = 4s

To get the acceleration of the car, we will substitute the given parameters into the given equation.

S = ut + 1/2at²

20 = 0(4)+1/2a(4)²

20 = 0+ a/2*16

20 = 8a

divide both sides by 8

20/8 = 8a/8

20/8 = a

a = 20/8

a = 2.5m/s²

Hence the acceleration of the car is 2.5m/s²

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: