A press release describing the 1986 nonstop, round-the-world trip by the aircraft voyager including the following data: flight distance: 25,012 miles
flight time: 9 days, 3 min., 44 seconds
fuel capacity: nearly 9000 lbs.
fuel remaining at the end of flight: 14 gal.
To the maximum number of significant figure permitted, calculate:
a.) the average speed of the aircraft in miles per hour
b.) the fuel consumption in miles per pound of fuel
(assume a density of 0.70 g/mL for the fuel.)

a.) the average speed of the aircraft in miles per hour

115.76 miles/ hour

b.) the fuel consumption in miles per pound of fuel

(assume a density of 0.70 g/mL for the fuel.)

2.8 miles/Ib of fuel

Step-by-step explanation:

A press release describing the 1986 nonstop, round-the-world trip by the aircraft voyager including the following data:

flight distance: 25,012 miles

flight time: 9 days, 3 min., 44 seconds

fuel capacity: nearly 9000 lbs.

fuel remaining at the end of flight: 14 gal.

To the maximum number of significant figure permitted, calculate:

a.) the average speed of the aircraft in miles per hour

Step 1

We convert the time to hours

flight time: 9 days, 3 min., 44 seconds

1 day = 24 hours

9 days =

24 × 9

= 216 hours

60 mins = 1 hour

3 mins =

3/60 = 1/20 = 0.05 hours

1 hour = 60 minutes

1 minute = 60 seconds

1 hour = 60 × 60 = 3600 seconds

If 3600 seconds = 1 hour

44 seconds =

= 44/3600

= 0.0122222222 hours

Total number of hours spent = (216 + 0.05 + 0.0122222222) hours

= 216.06222222 hours

Speed = Distance/Time

= flight distance: 25,012 miles

Speed = 25,012 miles/ 216.06222222hours

= 115.76294895 miles/ hour

Approximately = 115.76 miles/ hour

b.) the fuel consumption in miles per pound of fuel

(assume a density of 0.70 g/mL for the fuel.)

Step 1

We determine how much fuel is used

We have 14 gallons of fuel left over

1 gallon = 3.785 litres

14 gallons =

Cross Multiply

14 gallons × 3.785 liters/1 gallon

= 52.9958 liters

Note that density of fuel =

0.70 g/ml

1 gram / millilitre = 1 kilogram / litre

Hence, 0.7g/ml = 0.7 kg/L

Hence,the mass of fuel left = 52.9958 liters * 0.7 = 37.09706kg

1 kilogram = 2.205 pounds

37.09706kg =

37.09706kg × 2.205 pounds

= 81.7990173 lbs

Since the full capacity = 9000 lbs

The fuel used = 9000 - 81.7990173 lbs

= 8918.2009827 lbs

Hence, fuel consumption is

Distance/ amount of fuel used

25012/8918.2009827 lbs = 2.8046015164 miles/lb of fuel

Approximately = 2.8 miles/Ib of fuel

all but the second one

step-by-step explanation:

cuz that one goes over 180

mark brainliest

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following