, 
and 
):
, 
and 
, 
- Area of the triangle, measured in square centimeters. 
- Semiperimeter of the triangle, measured in centimeters.
, 
, 
- Sides of the triangle, measured in centimeters.
, 
, 
, 
, 
.
- Angles opossed to sides ![A = \cos^{-1}\left[\frac{(64.952\,cm)^{2}+(60\,cm)^{2}-(5\,cm)^{2}}{2\cdot (64.952\,cm)\cdot (60\,cm)} \right]](/tpl/images/0774/4944/e673a.png)
![B = \cos^{-1}\left[\frac{(5\,cm)^{2}+(60\,cm)^{2}-(64.952\,cm)^{2}}{2\cdot (5\,cm)\cdot (60\,cm)} \right]](/tpl/images/0774/4944/958a7.png)
![A = \cos^{-1}\left[\frac{(55.057\,cm)^{2}+(60\,cm)^{2}-(5\,cm)^{2}}{2\cdot (55.057\,cm)\cdot (60\,cm)} \right]](/tpl/images/0774/4944/30b4e.png)
![B = \cos^{-1}\left[\frac{(5\,cm)^{2}+(60\,cm)^{2}-(55.057\,cm)^{2}}{2\cdot (5\,cm)\cdot (60\,cm)} \right]](/tpl/images/0774/4944/32818.png)
Triangle ABC has an area of 25√3/2 cm²,c=60•, a=5cm
find the angle of A and B...
Mathematics, 21.09.2020 09:01 robert7248
Triangle ABC has an area of 25√3/2 cm²,c=60•, a=5cm
find the angle of A and B
Answers: 2
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