What do you remember? You have seen a figure very similar to this one in a in
previous lesson. Points A and B are each at the centers
of circles of radius AB. Compare EA and EB. Explain
your reasoning.
✓

EA and EB are equal

Step-by-step explanation:

This is because both of the circles have the same radius AB. The radius is the length from the center of a circle to anywhere on the edge of the circle and is the same no matter where on the circle it is measured from, as long as it goes to the middle. If we focus on just the circle with B at its center, we can see that AB is the radius from the middle to the edge of the circle at A. E also lies on the edge of this same circle, meaning that the length from B to E is that same as AB, the radius. The same logic applies to AE, the length AE is equal to the radius AB because it also runs from the center to the edge of the circle.

Therefore, EA and EB are equal, because they are both radii of two same size circles and are equal to the length of AB.

Hope this helped!

the f

last graph i believe

step-by-step explanation:

worked it out i believe

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92