Barbie and Woody go from school to a swimming pool, starting at the same time. Barbie walks at 70 meters per minute and
Woody cycles 3 times as fast as Barbie walks. 9 minutes later,
Woody arrives. How many minutes earlier than Barbie does
Woody arrive?

Woody arrived  

27 -  9 =  18  minutes before Barbie did.

Step-by-step explanation:

When you are working with Distance=speed-time problems remember that if you know two of the values you can calculate the third one,

Barbie: She walks at a speed of  70  metres per minute.  

Woody: Cycles  3  times as fast:   →3 × 70 = 210 m/min

He cycled for  9  minutes.

210 m/min is his speed.

9  minutes is the time he took.

Distance  =  speed  ×  time

D  =  210  × 9   =  1890  metres,

Barbie: walked the same distance of  1890  metres

Her speed was  70  m/min

The time she took:  

Time=

T i m e  =   =  27  minutes.

Woody arrived  27  −  9  =  18  minutes before Barbie did.

answer: 40.95

step-by-step explanation:

well my understanding of this question is they want you to use the y=14.1x -2.3 and put the coordinates they gave you onto the line segment of   y=14.1x -2.3

step-by-step explanation: