Mathematics, 20.09.2020 14:01 helpmeplz33
Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 2 cos(t) + sin(2t),[0, π/2].
Answers: 2
and the absolute minimum value is 
both sides w.r.t. 
,
![\Rightarrow 1-2\sin ^2t =\sin t \quad \quad [\because \cos 2t = 1-2\sin ^2t]](/tpl/images/0771/3959/9f314.png)
, the answer to this problem is 
w.r.t. 
![\Rightarrow \left[f''(t)\right]_{t=\frac {\pi}6}=-2\times \frac {\sqrt 3}2-4\times \frac{\sqrt 3}2=-3\sqrt 3](/tpl/images/0771/3959/30c32.png)
and minimum at 
![\left[f(t)\right]_{t=\frac {\pi}6}=2\times \frac {\sqrt 3}2+\frac{\sqrt 3}2=\frac{3\sqrt 3}2\;\text{and}\;\left[f(t)\right]_{t=\frac{\pi}2}= 2\times 0+0=0](/tpl/images/0771/3959/3bb81.png)
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Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 2 cos(t) +...
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