The gas mileage of an automobile first Increases and then decreases as the speed increases. Suppose that this relationship is very regular, as shown by the following data on speed (miles per hour) and mileage (miles per gallon):
Speed 30 40 50 60 70
Mileage 24 28 30 28 24
Data Set
Make a scatterplot of mileage versus speed. Show that the correlation between speed and mileage is r = 0.

Which statement explains why the correlation is o even though
there is a strong relationship between speed and mileage?

1. Correlation does not describe curved relationships between variables, no matter how strong they are.
2. Correlation is never a measure of the strength of the relationship between two variables.
3. Since the correlation is Othere is no strong relationship between speed and mileage; the scatterplot is misleading.
4. The correlation can be 0 even if there is a strong linear relationship between the variables.
5. Correlation only measures the strength of the relationship between two variables when the units of the two variables are the same.

b.

step-by-step explanation:

i just know

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.