You invested $29000in two accounts paying 3% and 8% annual interest, respectively. If the total interest earned for the year was $1270, how much was invested at each rate?

Amount invested at 3%= $21,000

Amount invested at 8% = $8,000

Step-by-step explanation:

$29,000 was invested in two accounts

The two accounts have annual interest of 3% and 8%

The total interest that was earned for the year is $1,270

Let y represent the amount invested at 3%

y = 3%

The amount invested at 8% can be represented as

29,000-y

Therefore the value of y can be calculated as follows

3/100 × y + 8/100(29,000-y)= 1270

0.03y + 0.08(29,000-y)= 1270

0.03y + 2320 - 0.08y= 1270

0.03y - 0.08y= 1270-2320

-0.05y= -1050

y = 1050/0.05

y= 21,000

The amount invested at 3% is $21,000

The amount invested at 8%

= 29,000-21,000

= $8000

Hence the amount invested at 3% is $21,000 and the amount invested at 8% is $8000

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation:

9 sandwiches per hour

step-by-step explanation:

when we have a rate, we want a 1 in the denominator

27/3 = 9

27 sandwiches/ 3 hours = 9 sandwiches/hour