a man has a box of coins that he uses when playing poker with friends. the box currently contains 30 coins, consisting of pennies, dimes, and quarters. the number of pennies is equal to the number of dimes, and the total value is $3.21.how many of each denomination of coins does he have?

Number of pennies = 11

Number of dimes = 11

Number of quarters = 8

Step-by-step explanation:

Given:

Total number of coins = 30

Number of pennies = Number of dimes

Total value = $3.21 = 321 penny

Computation:

Assume:

Number of pennies = x

So,

Number of dimes = x

Number of quarters = 30 -x- x = 30 - 2x

Value of pennies = x

Value of dimes = 10 x

Value value of quarters = 25[30 - 2x] = 750 - 50 x

Total value = x + 10x + 750 - 50x

39x = 429

x = 11

Number of pennies = 11

Number of dimes = 11

Number of quarters = 30 - 11 -11 = 8

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

idk

step-by-step explanation:

i don't know