A survey shows that 30% of the residents of a particular town read the morning paper 25% read the afternoon paper, and 10% read both. A. One resident is randomly selected. What is the probability that this person reads only the morning paper?
B. Given that a random resident reads the morning paper, what is the probability that this resident also reads the afternoon paper?

A) 0.20

B) 0.06

Step-by-step explanation:

From the question above we have the following information;

30% of the residents of a particular town read the morning paper

Probability (of the residents that read morning paper) = 0.3

25% read the afternoon paper

Probability (of the residents that read afternoon paper) = 0.25

10% read both

Probability (of the residents that read both) = 0.10

A. One resident is randomly selected. What is the probability that this person reads only the morning paper?

Probability( that this person reads only the morning paper) = Probability (of the residents that read morning paper) - Probability (of the residents that read both)

= 0.30 - 0.10

= 0.20

B. Given that a random resident reads the morning paper, what is the probability that this resident also reads the afternoon paper?

Probability( that this resident also reads the afternoon paper) = Probability (of the residents that read morning paper) × Probability (of the residents that read afternoon paper)

= 0.30 × 0.20

= 0.06

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29