A small family home in Tucson, Arizona has a rooftop area of 1967 square feet, and it is possible to capture rain falling on about 61.0% of the roof. A typical annual rainfall is about 14.0 inches. If the family wanted to install a tank to capture the rain for an entire year, without using any of it, what would be the required volume of the tank in m3 and in gallons

Required of volume of tank = 39.62 m3 or 10471.18   gallons

Step-by-step explanation:

Total volume of water collected = Annual Rainfall * Useful Area

Total volume of water collected = 1199.87 * 1.1667

Total volume of water collected = 1399.89 ft3

---1 ft3 = 7.48 gallons

Hence, total volume of water collected in gallons = 1399.89 * 7.48 = 10471.178  gallons

1 ft3 = 1/35.315 m3 = 0.0283 m3  

Therefore total volume of water collected in m3 = 1399.89 * 0.0283 = 39.6169 m3

Workings

Useful area = 61% of 1967

Useful area = 0.61 * 1967

Useful area = 1199.87 sq/ft.

Annual rainfall = 14 inch = 14/12 month

Annual rainfall = 1.1667 ft.

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step-by-step explanation:

(2,20) means that the 2 is 2 hours and 20 is 20$. so there both 20$ for 2 hours only the same price. like it says. so, the dunk tank and the bounce house are the same price (20$) for the same amount of time (2 hours).

hope i