A basketball player makes 80% of his free throws. We set him on the free throw line and told him to shoot free throws until he misses. Let the random variable X be the number of free throws taken by the player until he misses. Assuming that his shots are independent, what is the probability of this player missing a free throw for the first time on the fifth attempt

0.08192

Step-by-step explanation:

Given: Probability of free throws = 0.80

Then, probability of missing the free throw = 1-0.80=0.20

Now, According to the negative binomial probability distribution, the probability that the rth success is achieved in xth trial is given by ;-

Put p = 0.20 , x=5 and r =1, we get

The probability of this player missing a free throw for the first time on the fifth attempt as

hence the required probability =0.08192

25.2

step-by-step explanation:

2+4x6-8/10= 25.2

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,