There are nine different positions on a baseball team. If a team has 17 players how many different line-ups can the team make? (Assume every player can play every position.) The team can make different line-ups. Baseball games consist of nine innings. A team wants to change its line-up every inning. If no game goes to extra innings, and a season consists of 147 games, how many complete seasons can the team play without repeating a line-up? The team can play complete seasons without repeating a line-up. (Your answer should be an integer.)

A) 24310

B) 18 seasons

Step-by-step explanation:

A) We are given the team has 17 players and there are 9 different positions in the team.

This is a combination question and thus, the number of different line-ups the team can make is;

C(17, 9) = 24310

B) We are told the basketball games consists of 9 innings.

Thus,

Number of games you can fill = 24310/9 = 2701.1111

And then we are told a season consists of 147 games.

Thus;

Number of complete seasons can the team play without repeating a line-up =

2701.1111/147 ≈ 18 seasons

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation:

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!