pqrs is a rectangle with sides ps=5cm and pq =12cm find the length of qr ,sr and the two diagonals pr and qs.

PQRS is a rectangle.

PS = 5cm

PQ = 12cm

The length of qr ,sr and the two diagonals pr and qs.

Opposite sides of a rectangle are equal.

QR = PS = 5cm

SR = PQ = 12cm

By using Pythagoras Theorem, we get

PR = √PS^2 + SR^2

or, PR = √25 + 144

or, PR = √169

or, PR = 13cm

Diagonals of a rectangle are equal.

QS = PR = 13cm

QR = 5 cm

SR = 12 cm

PR = 13 cm

QS = 13 cm

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )