odds against a randomly chosen household having a cat if the probability of the event that a randomly chosen household has a cat is .21

Step-by-step explanation:

Odds against = failures / successes

Probability = successes / (successes + failures)

0.21 = cats / (cats + no cats)

1 / 0.21 = (cats + no cats) / cats

4.76 = 1 + (no cats / cats)

3.76 = no cats / cats

So the odds against are 3.76 to 1.  

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation:

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

happy to

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