Terry bought a home that home that had an attached one-car garage and a screened porch that spanned the length of the home. If the garage measured 16' in depth which was half the depth of the house and the screened porch was 64' in width, what is the GLA of the house?

2048SF

Step-by-step explanation:

From the question, we are informed that Terry bought a home that home that had an attached one-car garage and a screened porch that spanned the length of the home.

We are further told that the garage measured 16' in depth which was half the depth of the house and the screened porch was 64' in width. Since the garage measured 16' in depth which was half the depth of the house, this means that the total depth of the house will be:

= 16' × 2

= 32'

Therefore, the GLA of the house will then be the full depth of the house multiplied by the screened porch. This will be:

= 32' × 64'

= 2048SF

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation:

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