Suppose LCM(a, b) = 20160, a=60. Find the smallest possible value of b.

see below

Step-by-step explanation:

given:

LCM(a,b) = 20160, a=60

find:

smallest possible value of b

solution;

60, b = 20,160

b = 20,160 / 60

b = 336

60 x 336 = 20,160

= 2⁶ x 3² x 5 x 7

= (2² x 3 x 5) x (2⁴ x 3 x 7)

= (60) x (336)

LCM(60,336) = 1680

consider the 2² x 3 to get the prime number:

= 336 x 12

= 4032

therefore,

LCM(60,4032) = 20160

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

a

step-by-step explanation:

the answer is a