Suppose an object is launched from an initial height of h0, in meters, with initial velocity v0, in meters per second. The height of the object after t seconds is given by the equation h(t) = − 1 2 gt2 + v0t + h0, where g is the acceleration downward produced by gravity. The velocity of the object at time t is v(t) = −gt + v0.

c. 16 units

step-by-step explanation:

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3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

26?

step-by-step explanation:

answer: -8.2562234e+13