Given y2 + 5y - 6 = (y + p)(y +q) find the
values of p and q.

p = 6, q = - 1

Step-by-step explanation:

Factor the left side and compare to right side

y² + 5y - 6

Consider the factors of the constant term (- 6) which sum to give the coefficient of the y- term (+ 5)

The factors are + 6 and - 1, since

6 × - 1 = - 6 and 6 - 1 = + 5, thus

y² + 5y - 6 = (y + 6)(y - 1)

Compare with (y + p)(y + q) , then

p = 6 and q = - 1

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.