Find the smallest square number divisible by each of these numbers 6,9,and 15

900

6 = 2×3

9 = 3²

15 = 3×5

lcm = 2×3²×5 = 90

to have a square number multiple of 90 we have to multiply by 2 and 5

2×3²×5 × 2×5 = 2²×3²×5² = (2×3×5)² = 30² = 900

Good luck !

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

i think the answer is b.

step-by-step explanation:

not 100% sure though.