(8a power of 6) times (a power of 4) over (4a power of -3)

a x (4a)^12

Step-by-step explanation:

(8a)^6 x a^4

(4a)^-3

= (8a)^6 x a^4 x (4a)^3

= 8^6 x a^6 x a^4 x 4^3 x a^3

Collect like terms

= 8^6 x 4^3 x a^6 x a^4 x a^3

= (2 x 4)^6 x 4^3 x a^(6 + 4 + 3)

= 2^6 x 4^6 x 4^3 x a^13

= (2^2)^3 x 4^6 x 4^3 x a^13

= 4^3 x 4^6 x 4^3 x a^13

= 4^(3 + 6 + 3) x a^13

= 4^12 x a^13

= a x (4a)^12

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation: