The mean of 6 numbers is 3 the median is 6. List the numbers

Step-by-step explanation:

We have 6 numbers, the mean is the average of all 6, so adding all 6 numbers together and dividing by 6 will give you 3. Because of this we know the 6 numbers will have to add up to 18.

The median is the middle number, but we have an even number so the median is found by adding the 2 middle numbers and dividing by 2.

Because the mean is low, we can guess the first 2 numbers will be small, so let's try 1.  

1 + 1 + _ + _ + _ + _

The remaining 4 numbers will have to add up to 16, and the next 2 numbers need to add up to 12. There would not be any possible combination where this would work. Now we know our first 2 numbers are too big.

Now we try 0.

0 + 0 + _ + _ + _ + _

Now our remaining 4 numbers neet to be 18, but the middle 2 need to add to 12 (so when we divide by 2 we get 6) so 0 is still too big!

-2 + -2 + _ + _ + _ + _  

If we try -2 now the next 4 numbers need to add to 22, but that's still not going to work because 22-12 = 10 and the last 2 numbers have to be the same, or larger than the middle 2.

-3 + -3 + _ + _ + _ + _  

With -3 then our total of the remaining 4 numbers needs to be 24 and 24-12 = 12 so this could be an option!

Our numbers could be:

-3, -3, 6, 6, 6, 6

Let's check:

-3 + -3 + 6 + 6 + 6 + 6 = 18   18/6 = 3    and our middle 2 numbers are 6 so our median would be 6.

If the numbers all have to be different we can come up with a different solution by making our first 2 numbers smaller.

-9, -5, 5, 7, 9, 11  

Let's check

-9 + -5 + 5 + 7 + 9 + 11

-14 + 32 = 18  mean  18/6 = 3      median 5+7 = 12 and 12/2 = 6

So that could also work! There are actually many options that would be correct!

step-by-step explanation:

their are no angles. sorry cant .

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!