Mathematics, 20.09.2020 02:01 beserkerbradley5863

By 3:00pm, the temperture had increased by another 5 degrees. Was the temperture at 3:00pm positive or negative? How do you know?What was the temperture at 3:00pm.

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Answer from: Quest

answer: 10 meter

step-by-step explanation:

need details

Answer from: Quest

Answer: question no. 1 -a. yes, the sides are in the ratio 2 : 5.question no. 2 -b. 59°question no. 3 -c. angles x and y are remote interior angles.question no. 4 -d. 90°, 45° and 45°question no. 5 -b. mn and qrstep-by-step explanation: question no. 1 -rs : xu = 3 : 7.5 = 2 : 5rt : x? = 6.4 : 16 = 2 : 5st : u? = 6 : 15 = 2 : 5as the ratios of all sides are equivalent, the triangles must be congruent and the sides must be proportional.therefore, the answer is: a. yes, the sides are in the ratio 2 : 5.question no. 2 -in the second diagram, angle b is the only letter not shown. therefore, the number must be equivalent to angle b.if we substitute the value of angle b as being 22° in the first diagram, we can now use the angle sum of a triangle to obtain the value of angle a.angle sum of a triangle = 180°therefore: let angle a = aa + 99 + 22 = 180a = 180 - 99 - 22a = 59°therefore, the answer is: b. 59°question no. 3 -angles x and y don't share the vertex of the triangle with the exterior angle w. remote interior angles don't share a vertex of a triangle with an exterior angle. this means that angles x and y are remote interior angles.therefore, the answer is: c. angles x and y are remote interior angles.question no. 4 -the sum of all interior angles of a triangle must be equivalent to 180°.90°, 45° and 45° are the only set of angle measures that are equivalent to 180°.therefore, the answer is: d. 90°, 45° and 45°question no. 5 -the only pair of sides stated in the options which are corresponding are mn and qr.therefore, the answer is: b. mn and qr.

Answer from: Quest

isocolese triangle

we know that the line connect a and b is the hyptonuse

so first find the hypotonuse length using the distance formula, call the length c

since it is an isocolese triangle, the lengths of the legs are the same

using pythagorean theorem, $a^2+b^2=c^2$

in this case, a=b since isocolese triangle so we get

$2a^2=c^2$ or $a=\frac{c}{\sqrt{2}}$

we can find c so we can find the distances

we know that if we draw 2 circles, each has center at a and b, and find where they intersect, we can the 2 possible locations for c

if a has center at (xa,ya) and b has center at (xb,yb), then we can solve where

$(x-x_a)^2+(y-y_a)=(\frac{c}{\sqrt{2}})^2$ and

$(x-x_b)^2+(y-y_b)^2=(\frac{c}{\sqrt{2}})^2$ intersect to find where they intersect

i'm not going to put an example because i have to go to class. i hope this explanation is enough

Answer from: Quest

the answer is d.x= 90°

y= 50°

arc lm= 100°

i got this one chief

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By 3:00pm, the temperture had increased by another 5 degrees. Was the temperture at 3:00pm positive...

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