Mathematics, 15.10.2019 01:00 ajfijeoinf2750

Angle 1 and angle 2 are supplementary angles. m angle 1 is 4y+7. and m angle 2 is 9y+4. find the measure of angle 2
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Supplementary angles equals 180 degrees. Equal it to 4y+7+9y+4=180. Compine like terms 13y+11=180. Subtract both sides by 11. 13y=169. Divide by 13. Y=13. plug it into the measure of angle 2 (9y+4). 9(13)+4 will give you the answer.

Answer from: gungamer720

the measure of the angle 2 is 121 degrees

Step-by-step explanation:

Hello

Supplementary angles are two angles whose measurements add up to 180

m1+m2=180

m1 and m2 are supplementary angles

Step 1

Let

m1+m2=180

(1)m1=4y+7

(2)m2=9y+4

hence

4y+7+9y+4=180

resolving for y

13y+11=180

subtract 11 in each side

13y+11-11=180-11

13y=169

Now, divide each side by 13

(13y)/13=169/13

y=13

Step 2

Now , put the value of y=13 in (1) and (2) to find m1 and m2

(1)m1=4y+7

m1=4(13)+7

m1=59

m2=9y+4

m2= 9(13)+4

m2=117+4

m2=121

the measure of the angle 2 (m2) is 121 degrees

have a great day.

Answer from: Quest

(2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))

step-by-step explanation:

simplify the following:

x/x^2 + 3 x + 2 - (x (x + 1))/(x + 2)

combine powers. x/x^2 = x^(1 - 2):

x^(1 - 2) + 3 x + 2 - (x (x + 1))/(x + 2)

1 - 2 = -1:

x^(-1) + 3 x + 2 - (x (x + 1))/(x + 2)

put each term in 1/x + 3 x + 2 - (x (x + 1))/(x + 2) over the common denominator x (x + 2): 1/x + 3 x + 2 - (x (x + 1))/(x + 2) = (x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)):

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2))

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)) = ((x + 2) + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2)):

(2 + x + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

3 x^2 (x + 2) = 3 x^3 + 6 x^2:

(2 + x + 3 x^3 + 6 x^2 + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

2 x (x + 2) = 2 x^2 + 4 x:

(2 + x + 6 x^2 + 3 x^3 + 2 x^2 + 4 x - x^2 (x + 1))/(x (x + 2))

-x^2 (x + 1) = -x^2 - x^3:

(-x^2 - x^3 + 3 x^3 + 6 x^2 + 2 x^2 + 4 x + x + 2)/(x (x + 2))

grouping like terms, 3 x^3 - x^3 + 6 x^2 + 2 x^2 - x^2 + 4 x + x + 2 = (3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2:

((3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

3 x^3 - x^3 = 2 x^3:

(2 x^3 + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

6 x^2 + 2 x^2 - x^2 = 7 x^2:

(2 x^3 + 7 x^2 + (x + 4 x) + 2)/(x (x + 2))

x + 4 x = 5 x:

answer: (2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))

Answer from: Quest

yes

step-by-step explanation:

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Angle 1 and angle 2 are supplementary angles. m angle 1 is 4y+7. and m angle 2 is 9y+4. find the mea...