Lyle wants to build a rectangular dog pen with a length that is 12 feet more than the width. Lyle can afford no more than 560 feet of fence. Write an inequality to show that the perimeter of the dog pen can be no more than 560 feet.
2 (12 + w) + 2w < 560
(12 + 2) + w < 560
o 2(12 + w) + 2w< 560
0 (12+w) + w < 560

2(2W+12) < 560

Step-by-step explanation:

Perimeter of a rectangular dog pen P = 2(L+W) where;

L is the length of the dog pen

W is the width of the dog pen

If Lyle wants to build a rectangular dog pen with a length that is 12 feet more than the width, then L = W+12

If Lyle can afford no more than 560 feet of fence, this means that the perimeter cannot be more than 560feet i.e P<560

The inequality to show that the perimeter of the dog pen can be no more than 560 feet is expressed as P < 2(L+W)

Substituting the given parameters;

2([W+12]+W)<560

2(2W+12)<560

Hence the inequality to show that the perimeter of the dog pen can be no more than 560 feet is 2(2W+12)<560

x = 10.1

step-by-step explanation:

all of the angles of a tirangle add up to 180º

180 - 65 = 115 (since we already know the value of one angle)

(2x + 7) + (8x + 7) = 115

(combins like terms) 10x + 14 = 115

(isolate the variable subtract 14 from both sides): 10x = 101

(find the variable divide both sides by 10): x = 101/10

x = 10.1

3,000,540

step-by-step explanation: