Write the values that make the denominators zero. then solve the equation? 10/5x-5 + 1/5 = 2/x-1

  denominators are zero for x=1

  there is no solution

Step-by-step explanation:

We suspect your equation is supposed to be ...

  10/(5x -5) +1/5 = 2/(x -1) . . . . . parentheses are required on denominators

The denominators will be zero for x=1.

This version of the equation has no solution. It simplifies to ...

  2/(x-1) + 1/5 = 2/(x -1)

  1/5 = 0 . . . . . subtract 2/(x-1) from both sides

There is no value of x that will make this equation true.

_____

Alternative interpretation

The way your equation is written, it must be interpreted according to the order of operations to be ...

  (10/5)x -5 +1/5 = (2/x) -1 . . . . x=0 makes the denominator zero

  2x -3.8 = 2/x

  2x^2 -3.8x = 2 . . . . multiply by x

  2(x^2 -1.9x +.95^2) = 2 +2(0.95^2)

  (x -0.95)^2 = 1.9025

  x = 0.95 ± √1.9025 ≈ {-0.4293, 2.3293}

step-by-step explanation:

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d