Arectangle has a length 6 meters longer than double the width. the perimeters is i44 meters. find the dimensions of the rectangle

Use the information to form an equation
x = width
x + 6 = length
perimeter = length + length + width + width
x + x + x + 6 + x + 6 = 44
4x + 12 = 44
4x = 32
x = 32/4
x = 8
width = 8 meters
length = 8 + 6 = 14 meters

Idon’t know actually is more difficult