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Mathematics, 20.09.2020 18:01 Jonah58

Solve for g. 6(-2g-1)=-(13g+2)6(βˆ’2gβˆ’1)=βˆ’(13g+2)6 , left parenthesis, minus, 2, g, minus, 1, right parenthesis, equals, minus, left parenthesis, 13, g, plus, 2, right parenthesis g =g=g, equals

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Solve for g. 6(-2g-1)=-(13g+2)6(βˆ’2gβˆ’1)=βˆ’(13g+2)6 , left parenthesis, minus, 2, g, minus, 1, right pa...
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