Write the equation g(x) of the transformation of the parent graph f(x) = |x| stretched vertically by a factor of 4 and translated up 2 units.

g(x) = 4|x| +2

Step-by-step explanation:

f(x) = |x|

y = f(x) + C  C > 0 moves it up

g(x) = |x| +2 moves it up 2 units

y = Cf(x)  C > 1 stretches it in the y-direction

g(x) = 4|x| +2 stretch by 4

We start off with: f(x) = |x|

c > 0 means move up

y = f(x) + c

2 units up

After: g(x) = |x| + 2

c > 1 means y-direction stretch

y = cf(x)

4 unit stretch

After: g(x) = 4|x| + 2

Best of Luck!

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

it would open into a square depending on the type of envelope i’m not sure about the second part