Find a formula for the general term an (not the partial sum) of each infinite series (with starting point of n = 1.)
4/12+1+1/22+1+4/32+1+1/42+1+

Answer and Explanation:

Solution: For the general term of each infinite series,

     n=1 and the series are:

4/12+1+1/22+1+4/32+1+1/42+1+……..

Let [4/12 +1] + [1/22 + 1] + [4/32+1] + [1/42+1] +………

Sum of infinite series= ∑n=1 [4/n+11 + 1/n] + [1/n+21 + 1/n] + [4/n+31 + 1/n] + [1/n+41 +1/n] +………..

For n=1.

my guess is

step-by-step explanation:

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.