Find a perimeter of the bouncy castle find the area of the bouncy castle 2X squared minus 3X +7 times X squared +4

The answer is below

Step-by-step explanation:

From the image attached, the length of the bouncy castle is X² +4 and the width is 2x² - 3x  +7

The bouncy castle is a rectangle. A rectangle is a quadrilateral in which opposite sides are equal and all the angles have equal measures. The diagonals of a rectangle also bisect each other. The perimeter of a rectangle = 2(length + breadth), Hence for the bouncy castle:

Perimeter of castle = 2(length + breadth) = 2(x² + 4 + (2x² - 3x  +7)) = 2(3x² - 3x + 11) = 6x² - 6x + 22

Perimeter of castle = 6x² - 6x + 22

The area of the castle = length × breadth = x² + 4 × (2x² - 3x  +7)) = 2x⁴ - 3x³ + 7x² + 8x² - 12x + 28 = 2x⁴ - 3x³ + 15x² - 12x + 28

no not all of them.

step-by-step explanation:

some of them have a square base.

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.