There are 50 chess-club students and 60 drama-club students. If we randomly select a student, let C be the event the student is in the chess club, and let D be the event the student is in the drama club. How many students must be in both the chess club and the drama club in order for C and D to be independent events

mxb67

step-by-step explanation:

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

well if you round, things become much more simple. round 5.95 to 6, 4.25 to 4, and 1.05 to 1. now, add 6+4+1 and that would equal 11. so the items together would equal to about $11.