How many pairs of consecutive natural numbers have a product of less than 40000? I am in 5th grade. This is supposed to be easy for me, but it's not. I would greatly appreciate any help at all. Thank you, Anonymous

There are 199 pairs of consecutive natural numbers whose product is less than 40000.

Step-by-step explanation:

We notice that such statement can be translated into this inequation:

Now we solve this inequation to the highest value of that satisfy the inequation:

The Quadratic Formula shows that roots are:

Only the first root is valid source to determine the highest possible value of , which is . Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.

investment b is an ordinary annuity with $3,909.64 in the account after one year.

step-by-step explanation: