The position vector of a and b are 2i-j+4k and I+3j+k then magnitude of vector ab is

The magnitude of vector ab |M| = √26

Step-by-step explanation:

Mathematically, the magnitude of the position vectors is the distance between the two position vectors.

So in this case;

|M| = √{(x2-x1)^2 + (y2-y1)^2 + (z2-z1)^2}

From the question;

(x1,y1,z1) = (2,-1,4)

(x2,y2,z2) = (1,3,1)

Substituting these values, we have

M = √(1-2)^2 + (3-(-1))^2 +(1-4)^2

M = √(1 + 16 + 9

M = √26

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.