Mathematics, 09.09.2020 08:01 Cleotilde14151
For the function f(x)=\frac{\sqrt{x-2}}{8}f(x)= 8 xβ2 , find f^{-1}(x)f β1 (x). f^{-1}(x)=\left(8\left(x+2\right)\r ight)^{2}f β1 (x)=(8(x+2)) 2 f^{-1}(x)=\left(8x\right)^{2}+2f β1 (x)=(8x) 2 +2 f^{-1}(x)=\left(8x+2\right)^{2}f β1 (x)=(8x+2) 2 f^{-1}(x)=8\left(x+2\right)^{2}f β1 (x)=8(x+2) 2
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For the function f(x)=\frac{\sqrt{x-2}}{8}f(x)= 8 xβ2 , find f^{-1}(x)f β1 (x). f^{-1}(x)=\left(8\...
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