Consider the experiment of tossing three coins. What is the probability of getting anything but one head and two tails?

5/8

Step-by-step explanation:

Use binomial probability:

P = nCr pʳ qⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

The number of trials is n = 3.

The number of heads is r = 1.

The probability of heads is p = ½.

The probability of getting 1 heads and 2 tails is:

P = ₃C₁ (½)¹ (1 − ½)³⁻¹

P = 3 (½) (½)²

P = 3/8

So the probability of not getting 1 heads and 2 tails is:

1 − P = 5/8