A. A parabola opening upward, shifted 8 units right, and 5 units down. b. A parabola with a stretch factor of 10, sitting with its vertex on the x-axis at x = -6.
c. A downward opening parabola with vertex (-7, -2) and a vertical compression of 0.6.

A) y=(x-8)^2-5

B)y=10(x+6)^2

C) y=-0.6(x+7)^2-2

Step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204