The angles in a triangle are such that one angle is 128 more than the smallest angle, while the third angle is 2 times as large as the smallest angle. Find the measures of all three angles.

We can write an equation using the information given in the problem.

2x + x + x + 128 = 180

Solve for x.

4x + 128 = 180

4x = 52

x = 13

Second angle:

13 + 128 = 141

Third angle:

13 * 2 = 26

Therefore, the answer is [ 13, 26, and 141 ]

Best of Luck!

■

a = 141°

b = 13°

c = 26°

■ Step-by-step explanation:

a = 128 + b

c = 2b

a + b + c = 128

replace a & c

(128 + b) + b + 2b = 180

4b = 180 - 128

4b = 52

b = 13°

a = 128° + 13° = 141°

c = 2×13° = 26°

step-by-step explanation:

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