Solve for z: 2+3(z-3) = z+3z+6z

Steps to solve:

2 + 3(z - 3) = z + 3z + 6z

~Distribute left side and simplify right side

2 + 3z - 9 = 10z

~Simplify left side

3z - 7 = 10z

~Subtract 3z to both sides

-7 = 7z

~Divide 7 to both sides

-1 = z

Best of Luck!

z=-1

Step-by-step explanation:

2+3(z-3)=z+3z+6z

2+3z-9=z+3z+6z

2+3z-9=10z

2-9=10z-3z

-7=7z

7 7

z=-1

Proof:

2+3(z-3)=z+3z+6z

2+3(-1-3)=-1+(-3)+(-6)

2+3(-4)=-1-3-6

2-12=-10

-10=-10

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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