Solve the inequality y^2-3y greater than 18 sorry couldn't find the greater than sign

y > 6 or y < -3

Step-by-step explanation:

y² - 3y > 18

Complete the square.

y² - 3y + 9/4 > 18 + 9/4

y² - 3y + 9/4 > 81/4

(y - 3/2)² > 81/4

y - 3/2 > 9/2, or y - 3/2 < -9/2

y > 6 or y < -3

The greater than sign (on my computer) is above the period key.  So, just jit SHIFT then type the period key.

So, I guess you want to solve y^2  -3y > 18

We can factor that as y * (y -3) > 18

Well, if it is

y^2 -3y -18 = 0 then

Then y = 6 and y = -3

Hope that helps

Step-by-step explanation:

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c