A car drives at 50 km/h from City P to City Q. 2 hours later, a motorcycle drives 75 km/h begins the same journey from City P to City Q, taking the same route as the car. How long does it take to catch up to the car?

4 hours

Step-by-step explanation:

d = r * t

t = t       for the second car. This is the time to catch the first car.

t = t + 2 for the first car

r = 50 km/h for the first car

r = 75 miles per hour.

The trick to this question is realizing that both cars have to go the same distance.

50*(t + 2) = 75 * t             Remove the brackets

50 t  + 100 = 75t              Subtract 50t from both sides

100 = 75t - 50 t

100 = 25t                         Divide by 25

100/25 = t

t = 4 hours.

What this is telling you is that the faster car will take 4 hours to catch the slower one.

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629