Consider the line - 3x + 7y=4. Find the equation of the line that is parallel to this line and passes through the point (-3, -4).
Find the equation of the line that is perpendicular to this line and passes through the point (-3, -4).

Parallel:  y = 3/7x - 17/7

Perpendicular:  y = -7/3x - 11

Step-by-step explanation:

Rearrange the given equation so that it is in slope-intercept form.

-3x + 7y = 4

7y = 3x + 4

y = 3/7x + 4/7

The slope of the line is 3/7.  A parallel line will have the same slope.  Using this slope and the given point, you can find an equation using point-slope form.

y - y₁ = m(x - x₁)

y - (-4) = 3/7(x - (-3))

y + 4 = 3/7(x + 3)

y + 4 = 3/7x + 9/7

y = 3/7x - 17/7

A perpendicular line will have a slope that is the negative inverse of the original slope.  This means that the slope will be -7/3.  Repeat above steps.

y - y₁ = m(x - x₁)

y - (-4) = -7/3(x - (-3))

y + 4 = -7/3(x + 3)

y + 4 = -7/3x - 7

y = -7/3x - 11

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

answer: 0.1,0.85

step-by-step explanation: