Mathematics, 06.09.2020 01:01 kcarstensen59070
The shape of a cancerous tumor is roughly spherical and has volume
V= 4/3 πr^3
where r is the radius in centimeters.
a. When first observed, the tumor has radius 0.73 cm, and 45 days later, the radius is 0.95 cm. By how much does the volume of the tumor increase during this period?
b. After being treated with chemotherapy, the radius of the tumor decreases by 23%. What is the corresponding percentage decrease in the volume of the tumor?
Answers: 1
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The shape of a cancerous tumor is roughly spherical and has volume
V= 4/3 πr^3
where r...
where r...
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