A projectile is fired straight up from ground level with an initial velocity of 112 ft/s. Its height, h, above the ground after t seconds is given by h = –16t2 + 128t. What is the interval of time during which the projectile's height exceeds 192 feet?

  (2, 6)

Step-by-step explanation:

We want h > 192, so ...

  -16t^2 +128t > 192

  t^2 -8t < -12 . . . . . . . divide by -16

  t^2 -8t +12 < 0 . . . . . add 12

  (t -6)(t -2) < 0 . . . . . . factor

The zeros of this are t=2 and t=6. The signs of the factors will be different, hence their product will be negative, for values of t between these zeros.

The projectile's height exceeds 192 feet in the interval 2 < t < 6.

f(x)=2/3x+4/3 is the answer because is whose power in the senate is equal to the power of the speaker of the house?

step-by-step explanation:

answer: sine

step-by-step explanation: