Trent train is traveling at the speed of 10m/s at the top of a hill. Five seconds later it reaches the bottom of the hill and is moving at 39 m/s. What is the rate of acceleration of Trent train?

The first thing to do before starting to solve any numerical is to write down all the information we have.

Initial speed (u) = 10 m/s

Final speed  (v) = 39 m/s

Time (t) = 5 seconds

To find acceleration(a):

We know the equation for the first Law of Motion:

v = u+a*t

Hence, we can rearrange this as:

a = (v-u)/t

On substituting the values given,

a = (39 - 10)/5

a = 29/5

a = 5.8 m/(s^2)

Hence, the acceleration of the train is 5.8 m/(s^2)

$450 is the answer.

step-by-step explanation:

30% of 450 = 135

450-135=315

b

step-by-step explanation: