How do I do this problem?

Step-by-step explanation:

∠CFE is made up of ∠3 + ∠4; therefore,

∠3 + ∠4 = 74

∠BFD is made up of ∠2 + ∠3; therefore,

∠2 + ∠3 = 103

∠BFE is made up of ∠2 + ∠3 + ∠4; therefore,

∠2 + ∠3 + ∠4 = 136

and we are looking for the measure of ∠CFD which is ∠3.

Begin by using the fact that ∠3 + ∠4 = 74 and sub that into ∠BFE:

∠BFE      =      136 and

∠2 + (∠3 + ∠4) = 136 and

∠2 + 74 = 136 so

∠2 = 62

Now use that in ∠BFD since

∠BFD    =      103 and

∠2 + ∠3 = 103 and

62 + ∠3 = 103 so

∠3 = 41

do you have any choices

step-by-step explanation:

the f

last graph i believe

step-by-step explanation:

worked it out i believe