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Mathematics, 04.09.2020 04:01 carlo123

Si f(x)=2x^{2}βˆ’3x+1 y g(x)=xβˆ’3. Entonces (f∘g)(βˆ’1) es:

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Si f(x)=2x^{2}βˆ’3x+1 y g(x)=xβˆ’3. Entonces (f∘g)(βˆ’1) es:...
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