In quadrilateral ABCD, the measure of angle A exceeds the measure of angle B by 20 degrees. Also, the measure of angle D is twice the measure of angle B and have the measure of angle C . Someone please help me answer this fast. Thank you

in any quadrilateral, the sum of the interior angles is 360 degrees, so angles

a+b+c+d = 360 degrees.

But a = 2b

and b = 2c

and c = 2d so...

b = 4d and

a = 8d so we have:

8d+4d+2d+d = 360

15d = 360 and

d = 24 degrees

c = 2(24) = 48 degrees and

b = 4(24) = 96 degrees and

a = 8(24) = 192 degrees.

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