Let f (x) = x2, g(x) = 2x – 1, and h (x) = 2 - 4

Evaluate g(f(-1)).

Idon't see any graph, however the graph of the function : f(x) = x²-2x+3 is a parabola: 1) open upward (since a> 0)2) it intersects y-axis in 3 (y=3)3) its axis of symmetry is x = +1 ( -b/2a)4) it's minimum is y = -2, so its vertex is (1,-2)5) it doesn't intersect the x-axis since discriminant < 0 

Yes she is correct. when you do 1/5 the tbe is their to represent the fraction. so yes, kathy got it