suppose the equation for line A is given by 2x-5y=15, if line A and B are parallel and the point (-10,3) lies on line B, then write the equation in slope intercept for line b.

y=2/5x + 7

Step-by-step explanation:

First, you have to rewrite 2x-5y=15 to slop intercept form.

To do that you have to first subtract 2x from both side to cancel it out.

2x- 2x-5y= 15 -2x.    

-5y= -2x+15

Next, you divide 5 on both side to leave the y by itself.

y= -2x/-5 + 15/-5

Simplify

y= 2/5x + (-3)                     2/5 is our slope

Now that we found the slope, we need to the y-intercept of line b

y=2/5x + b

To find the y-intercept, we substitue x and y with the coordinates (-10,3)

3= 2/5(-10) +b

Now we just solve for b

3= -4 +b

3-(-4) = b

7=b

Now we have identified that 7 is the y intercept

The full equation is y= 2/5x +7

I hope this helped :)

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